3.18.63 \(\int \frac {1}{(d+e x)^{5/2} (a d e+(c d^2+a e^2) x+c d e x^2)^{5/2}} \, dx\)

Optimal. Leaf size=457 \[ \frac {1155 c^4 d^4 e \sqrt {d+e x}}{64 \left (c d^2-a e^2\right )^6 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}+\frac {1155 c^4 d^4 e^{3/2} \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{\sqrt {d+e x} \sqrt {c d^2-a e^2}}\right )}{64 \left (c d^2-a e^2\right )^{13/2}}-\frac {385 c^3 d^3 e}{64 \sqrt {d+e x} \left (c d^2-a e^2\right )^5 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \sqrt {d+e x} \left (c d^2-a e^2\right )^3 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 (d+e x)^{3/2} \left (c d^2-a e^2\right )^2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {1}{4 (d+e x)^{5/2} \left (c d^2-a e^2\right ) \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \]

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Rubi [A]  time = 0.50, antiderivative size = 457, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 4, integrand size = 39, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {672, 666, 660, 205} \begin {gather*} \frac {1155 c^4 d^4 e \sqrt {d+e x}}{64 \left (c d^2-a e^2\right )^6 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}-\frac {385 c^3 d^3 e}{64 \sqrt {d+e x} \left (c d^2-a e^2\right )^5 \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \sqrt {d+e x} \left (c d^2-a e^2\right )^3 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {1155 c^4 d^4 e^{3/2} \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {x \left (a e^2+c d^2\right )+a d e+c d e x^2}}{\sqrt {d+e x} \sqrt {c d^2-a e^2}}\right )}{64 \left (c d^2-a e^2\right )^{13/2}}+\frac {11 c d}{24 (d+e x)^{3/2} \left (c d^2-a e^2\right )^2 \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}}+\frac {1}{4 (d+e x)^{5/2} \left (c d^2-a e^2\right ) \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((d + e*x)^(5/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2)),x]

[Out]

1/(4*(c*d^2 - a*e^2)*(d + e*x)^(5/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)) + (11*c*d)/(24*(c*d^2 - a*
e^2)^2*(d + e*x)^(3/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)) + (33*c^2*d^2)/(32*(c*d^2 - a*e^2)^3*Sqr
t[d + e*x]*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)) - (77*c^3*d^3*Sqrt[d + e*x])/(32*(c*d^2 - a*e^2)^4*(
a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(3/2)) - (385*c^3*d^3*e)/(64*(c*d^2 - a*e^2)^5*Sqrt[d + e*x]*Sqrt[a*d*e
+ (c*d^2 + a*e^2)*x + c*d*e*x^2]) + (1155*c^4*d^4*e*Sqrt[d + e*x])/(64*(c*d^2 - a*e^2)^6*Sqrt[a*d*e + (c*d^2
+ a*e^2)*x + c*d*e*x^2]) + (1155*c^4*d^4*e^(3/2)*ArcTan[(Sqrt[e]*Sqrt[a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2])/
(Sqrt[c*d^2 - a*e^2]*Sqrt[d + e*x])])/(64*(c*d^2 - a*e^2)^(13/2))

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 660

Int[1/(Sqrt[(d_.) + (e_.)*(x_)]*Sqrt[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]), x_Symbol] :> Dist[2*e, Subst[Int[1/(
2*c*d - b*e + e^2*x^2), x], x, Sqrt[a + b*x + c*x^2]/Sqrt[d + e*x]], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^
2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0]

Rule 666

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((2*c*d - b*e)*(d +
e*x)^m*(a + b*x + c*x^2)^(p + 1))/(e*(p + 1)*(b^2 - 4*a*c)), x] - Dist[((2*c*d - b*e)*(m + 2*p + 2))/((p + 1)*
(b^2 - 4*a*c)), Int[(d + e*x)^(m - 1)*(a + b*x + c*x^2)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^
2 - 4*a*c, 0] && EqQ[c*d^2 - b*d*e + a*e^2, 0] && LtQ[p, -1] && LtQ[0, m, 1] && IntegerQ[2*p]

Rule 672

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> -Simp[(e*(d + e*x)^m*(a +
b*x + c*x^2)^(p + 1))/((m + p + 1)*(2*c*d - b*e)), x] + Dist[(c*(m + 2*p + 2))/((m + p + 1)*(2*c*d - b*e)), I
nt[(d + e*x)^(m + 1)*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b^2 - 4*a*c, 0] && EqQ
[c*d^2 - b*d*e + a*e^2, 0] && LtQ[m, 0] && NeQ[m + p + 1, 0] && IntegerQ[2*p]

Rubi steps

\begin {align*} \int \frac {1}{(d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {(11 c d) \int \frac {1}{(d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx}{8 \left (c d^2-a e^2\right )}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {\left (33 c^2 d^2\right ) \int \frac {1}{\sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx}{16 \left (c d^2-a e^2\right )^2}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {\left (231 c^3 d^3\right ) \int \frac {\sqrt {d+e x}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{5/2}} \, dx}{64 \left (c d^2-a e^2\right )^3}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {\left (385 c^3 d^3 e\right ) \int \frac {1}{\sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{64 \left (c d^2-a e^2\right )^4}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {385 c^3 d^3 e}{64 \left (c d^2-a e^2\right )^5 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}-\frac {\left (1155 c^4 d^4 e\right ) \int \frac {\sqrt {d+e x}}{\left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}} \, dx}{128 \left (c d^2-a e^2\right )^5}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {385 c^3 d^3 e}{64 \left (c d^2-a e^2\right )^5 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {1155 c^4 d^4 e \sqrt {d+e x}}{64 \left (c d^2-a e^2\right )^6 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (1155 c^4 d^4 e^2\right ) \int \frac {1}{\sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}} \, dx}{128 \left (c d^2-a e^2\right )^6}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {385 c^3 d^3 e}{64 \left (c d^2-a e^2\right )^5 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {1155 c^4 d^4 e \sqrt {d+e x}}{64 \left (c d^2-a e^2\right )^6 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {\left (1155 c^4 d^4 e^3\right ) \operatorname {Subst}\left (\int \frac {1}{2 c d^2 e-e \left (c d^2+a e^2\right )+e^2 x^2} \, dx,x,\frac {\sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{\sqrt {d+e x}}\right )}{64 \left (c d^2-a e^2\right )^6}\\ &=\frac {1}{4 \left (c d^2-a e^2\right ) (d+e x)^{5/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {11 c d}{24 \left (c d^2-a e^2\right )^2 (d+e x)^{3/2} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}+\frac {33 c^2 d^2}{32 \left (c d^2-a e^2\right )^3 \sqrt {d+e x} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {77 c^3 d^3 \sqrt {d+e x}}{32 \left (c d^2-a e^2\right )^4 \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{3/2}}-\frac {385 c^3 d^3 e}{64 \left (c d^2-a e^2\right )^5 \sqrt {d+e x} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {1155 c^4 d^4 e \sqrt {d+e x}}{64 \left (c d^2-a e^2\right )^6 \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}+\frac {1155 c^4 d^4 e^{3/2} \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {a d e+\left (c d^2+a e^2\right ) x+c d e x^2}}{\sqrt {c d^2-a e^2} \sqrt {d+e x}}\right )}{64 \left (c d^2-a e^2\right )^{13/2}}\\ \end {align*}

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Mathematica [C]  time = 0.04, size = 83, normalized size = 0.18 \begin {gather*} -\frac {2 c^4 d^4 (d+e x)^{3/2} \, _2F_1\left (-\frac {3}{2},5;-\frac {1}{2};\frac {e (a e+c d x)}{a e^2-c d^2}\right )}{3 \left (c d^2-a e^2\right )^5 ((d+e x) (a e+c d x))^{3/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((d + e*x)^(5/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2)),x]

[Out]

(-2*c^4*d^4*(d + e*x)^(3/2)*Hypergeometric2F1[-3/2, 5, -1/2, (e*(a*e + c*d*x))/(-(c*d^2) + a*e^2)])/(3*(c*d^2
- a*e^2)^5*((a*e + c*d*x)*(d + e*x))^(3/2))

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IntegrateAlgebraic [F]  time = 180.06, size = 0, normalized size = 0.00 \begin {gather*} \text {\$Aborted} \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[1/((d + e*x)^(5/2)*(a*d*e + (c*d^2 + a*e^2)*x + c*d*e*x^2)^(5/2)),x]

[Out]

$Aborted

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fricas [B]  time = 0.49, size = 3078, normalized size = 6.74

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^(5/2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(5/2),x, algorithm="fricas")

[Out]

[1/384*(3465*(c^6*d^6*e^6*x^7 + a^2*c^4*d^9*e^3 + (5*c^6*d^7*e^5 + 2*a*c^5*d^5*e^7)*x^6 + (10*c^6*d^8*e^4 + 10
*a*c^5*d^6*e^6 + a^2*c^4*d^4*e^8)*x^5 + 5*(2*c^6*d^9*e^3 + 4*a*c^5*d^7*e^5 + a^2*c^4*d^5*e^7)*x^4 + 5*(c^6*d^1
0*e^2 + 4*a*c^5*d^8*e^4 + 2*a^2*c^4*d^6*e^6)*x^3 + (c^6*d^11*e + 10*a*c^5*d^9*e^3 + 10*a^2*c^4*d^7*e^5)*x^2 +
(2*a*c^5*d^10*e^2 + 5*a^2*c^4*d^8*e^4)*x)*sqrt(-e/(c*d^2 - a*e^2))*log(-(c*d*e^2*x^2 + 2*a*e^3*x - c*d^3 + 2*a
*d*e^2 + 2*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(c*d^2 - a*e^2)*sqrt(e*x + d)*sqrt(-e/(c*d^2 - a*e^2)))
/(e^2*x^2 + 2*d*e*x + d^2)) + 2*(3465*c^5*d^5*e^5*x^5 - 128*c^5*d^10 + 2048*a*c^4*d^8*e^2 + 2295*a^2*c^3*d^6*e
^4 - 1030*a^3*c^2*d^4*e^6 + 328*a^4*c*d^2*e^8 - 48*a^5*e^10 + 1155*(11*c^5*d^6*e^4 + 4*a*c^4*d^4*e^6)*x^4 + 23
1*(73*c^5*d^7*e^3 + 74*a*c^4*d^5*e^5 + 3*a^2*c^3*d^3*e^7)*x^3 + 99*(93*c^5*d^8*e^2 + 232*a*c^4*d^6*e^4 + 27*a^
2*c^3*d^4*e^6 - 2*a^3*c^2*d^2*e^8)*x^2 + 11*(128*c^5*d^9*e + 1162*a*c^4*d^7*e^3 + 345*a^2*c^3*d^5*e^5 - 68*a^3
*c^2*d^3*e^7 + 8*a^4*c*d*e^9)*x)*sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*sqrt(e*x + d))/(a^2*c^6*d^17*e^2
- 6*a^3*c^5*d^15*e^4 + 15*a^4*c^4*d^13*e^6 - 20*a^5*c^3*d^11*e^8 + 15*a^6*c^2*d^9*e^10 - 6*a^7*c*d^7*e^12 + a^
8*d^5*e^14 + (c^8*d^14*e^5 - 6*a*c^7*d^12*e^7 + 15*a^2*c^6*d^10*e^9 - 20*a^3*c^5*d^8*e^11 + 15*a^4*c^4*d^6*e^1
3 - 6*a^5*c^3*d^4*e^15 + a^6*c^2*d^2*e^17)*x^7 + (5*c^8*d^15*e^4 - 28*a*c^7*d^13*e^6 + 63*a^2*c^6*d^11*e^8 - 7
0*a^3*c^5*d^9*e^10 + 35*a^4*c^4*d^7*e^12 - 7*a^6*c^2*d^3*e^16 + 2*a^7*c*d*e^18)*x^6 + (10*c^8*d^16*e^3 - 50*a*
c^7*d^14*e^5 + 91*a^2*c^6*d^12*e^7 - 56*a^3*c^5*d^10*e^9 - 35*a^4*c^4*d^8*e^11 + 70*a^5*c^3*d^6*e^13 - 35*a^6*
c^2*d^4*e^15 + 4*a^7*c*d^2*e^17 + a^8*e^19)*x^5 + 5*(2*c^8*d^17*e^2 - 8*a*c^7*d^15*e^4 + 7*a^2*c^6*d^13*e^6 +
14*a^3*c^5*d^11*e^8 - 35*a^4*c^4*d^9*e^10 + 28*a^5*c^3*d^7*e^12 - 7*a^6*c^2*d^5*e^14 - 2*a^7*c*d^3*e^16 + a^8*
d*e^18)*x^4 + 5*(c^8*d^18*e - 2*a*c^7*d^16*e^3 - 7*a^2*c^6*d^14*e^5 + 28*a^3*c^5*d^12*e^7 - 35*a^4*c^4*d^10*e^
9 + 14*a^5*c^3*d^8*e^11 + 7*a^6*c^2*d^6*e^13 - 8*a^7*c*d^4*e^15 + 2*a^8*d^2*e^17)*x^3 + (c^8*d^19 + 4*a*c^7*d^
17*e^2 - 35*a^2*c^6*d^15*e^4 + 70*a^3*c^5*d^13*e^6 - 35*a^4*c^4*d^11*e^8 - 56*a^5*c^3*d^9*e^10 + 91*a^6*c^2*d^
7*e^12 - 50*a^7*c*d^5*e^14 + 10*a^8*d^3*e^16)*x^2 + (2*a*c^7*d^18*e - 7*a^2*c^6*d^16*e^3 + 35*a^4*c^4*d^12*e^7
- 70*a^5*c^3*d^10*e^9 + 63*a^6*c^2*d^8*e^11 - 28*a^7*c*d^6*e^13 + 5*a^8*d^4*e^15)*x), 1/192*(3465*(c^6*d^6*e^
6*x^7 + a^2*c^4*d^9*e^3 + (5*c^6*d^7*e^5 + 2*a*c^5*d^5*e^7)*x^6 + (10*c^6*d^8*e^4 + 10*a*c^5*d^6*e^6 + a^2*c^4
*d^4*e^8)*x^5 + 5*(2*c^6*d^9*e^3 + 4*a*c^5*d^7*e^5 + a^2*c^4*d^5*e^7)*x^4 + 5*(c^6*d^10*e^2 + 4*a*c^5*d^8*e^4
+ 2*a^2*c^4*d^6*e^6)*x^3 + (c^6*d^11*e + 10*a*c^5*d^9*e^3 + 10*a^2*c^4*d^7*e^5)*x^2 + (2*a*c^5*d^10*e^2 + 5*a^
2*c^4*d^8*e^4)*x)*sqrt(e/(c*d^2 - a*e^2))*arctan(-sqrt(c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)*(c*d^2 - a*e^2)*
sqrt(e*x + d)*sqrt(e/(c*d^2 - a*e^2))/(c*d*e^2*x^2 + a*d*e^2 + (c*d^2*e + a*e^3)*x)) + (3465*c^5*d^5*e^5*x^5 -
128*c^5*d^10 + 2048*a*c^4*d^8*e^2 + 2295*a^2*c^3*d^6*e^4 - 1030*a^3*c^2*d^4*e^6 + 328*a^4*c*d^2*e^8 - 48*a^5*
e^10 + 1155*(11*c^5*d^6*e^4 + 4*a*c^4*d^4*e^6)*x^4 + 231*(73*c^5*d^7*e^3 + 74*a*c^4*d^5*e^5 + 3*a^2*c^3*d^3*e^
7)*x^3 + 99*(93*c^5*d^8*e^2 + 232*a*c^4*d^6*e^4 + 27*a^2*c^3*d^4*e^6 - 2*a^3*c^2*d^2*e^8)*x^2 + 11*(128*c^5*d^
9*e + 1162*a*c^4*d^7*e^3 + 345*a^2*c^3*d^5*e^5 - 68*a^3*c^2*d^3*e^7 + 8*a^4*c*d*e^9)*x)*sqrt(c*d*e*x^2 + a*d*e
+ (c*d^2 + a*e^2)*x)*sqrt(e*x + d))/(a^2*c^6*d^17*e^2 - 6*a^3*c^5*d^15*e^4 + 15*a^4*c^4*d^13*e^6 - 20*a^5*c^3
*d^11*e^8 + 15*a^6*c^2*d^9*e^10 - 6*a^7*c*d^7*e^12 + a^8*d^5*e^14 + (c^8*d^14*e^5 - 6*a*c^7*d^12*e^7 + 15*a^2*
c^6*d^10*e^9 - 20*a^3*c^5*d^8*e^11 + 15*a^4*c^4*d^6*e^13 - 6*a^5*c^3*d^4*e^15 + a^6*c^2*d^2*e^17)*x^7 + (5*c^8
*d^15*e^4 - 28*a*c^7*d^13*e^6 + 63*a^2*c^6*d^11*e^8 - 70*a^3*c^5*d^9*e^10 + 35*a^4*c^4*d^7*e^12 - 7*a^6*c^2*d^
3*e^16 + 2*a^7*c*d*e^18)*x^6 + (10*c^8*d^16*e^3 - 50*a*c^7*d^14*e^5 + 91*a^2*c^6*d^12*e^7 - 56*a^3*c^5*d^10*e^
9 - 35*a^4*c^4*d^8*e^11 + 70*a^5*c^3*d^6*e^13 - 35*a^6*c^2*d^4*e^15 + 4*a^7*c*d^2*e^17 + a^8*e^19)*x^5 + 5*(2*
c^8*d^17*e^2 - 8*a*c^7*d^15*e^4 + 7*a^2*c^6*d^13*e^6 + 14*a^3*c^5*d^11*e^8 - 35*a^4*c^4*d^9*e^10 + 28*a^5*c^3*
d^7*e^12 - 7*a^6*c^2*d^5*e^14 - 2*a^7*c*d^3*e^16 + a^8*d*e^18)*x^4 + 5*(c^8*d^18*e - 2*a*c^7*d^16*e^3 - 7*a^2*
c^6*d^14*e^5 + 28*a^3*c^5*d^12*e^7 - 35*a^4*c^4*d^10*e^9 + 14*a^5*c^3*d^8*e^11 + 7*a^6*c^2*d^6*e^13 - 8*a^7*c*
d^4*e^15 + 2*a^8*d^2*e^17)*x^3 + (c^8*d^19 + 4*a*c^7*d^17*e^2 - 35*a^2*c^6*d^15*e^4 + 70*a^3*c^5*d^13*e^6 - 35
*a^4*c^4*d^11*e^8 - 56*a^5*c^3*d^9*e^10 + 91*a^6*c^2*d^7*e^12 - 50*a^7*c*d^5*e^14 + 10*a^8*d^3*e^16)*x^2 + (2*
a*c^7*d^18*e - 7*a^2*c^6*d^16*e^3 + 35*a^4*c^4*d^12*e^7 - 70*a^5*c^3*d^10*e^9 + 63*a^6*c^2*d^8*e^11 - 28*a^7*c
*d^6*e^13 + 5*a^8*d^4*e^15)*x)]

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^(5/2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(5/2),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Eval
uation time: 1.45Unable to transpose Error: Bad Argument Value

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maple [B]  time = 0.09, size = 1225, normalized size = 2.68

result too large to display

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(e*x+d)^(5/2)/(c*d*e*x^2+a*d*e+(a*e^2+c*d^2)*x)^(5/2),x)

[Out]

-1/192*(c*d*e*x^2+a*e^2*x+c*d^2*x+a*d*e)^(1/2)*(-12705*((a*e^2-c*d^2)*e)^(1/2)*x^4*c^5*d^6*e^4-16863*((a*e^2-c
*d^2)*e)^(1/2)*x^3*c^5*d^7*e^3-9207*((a*e^2-c*d^2)*e)^(1/2)*x^2*c^5*d^8*e^2-1408*((a*e^2-c*d^2)*e)^(1/2)*x*c^5
*d^9*e-3465*((a*e^2-c*d^2)*e)^(1/2)*x^5*c^5*d^5*e^5+128*((a*e^2-c*d^2)*e)^(1/2)*c^5*d^10+48*((a*e^2-c*d^2)*e)^
(1/2)*a^5*e^10-328*((a*e^2-c*d^2)*e)^(1/2)*a^4*c*d^2*e^8+1030*((a*e^2-c*d^2)*e)^(1/2)*a^3*c^2*d^4*e^6-2295*((a
*e^2-c*d^2)*e)^(1/2)*a^2*c^3*d^6*e^4-2048*((a*e^2-c*d^2)*e)^(1/2)*a*c^4*d^8*e^2+20790*arctanh((c*d*x+a*e)^(1/2
)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^2*a*c^4*d^6*e^5*(c*d*x+a*e)^(1/2)+13860*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2
)*e)^(1/2)*e)*x*a*c^4*d^7*e^4*(c*d*x+a*e)^(1/2)+3465*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^4*
a*c^4*d^4*e^7*(c*d*x+a*e)^(1/2)+13860*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^3*a*c^4*d^5*e^6*(
c*d*x+a*e)^(1/2)-88*((a*e^2-c*d^2)*e)^(1/2)*x*a^4*c*d*e^9+748*((a*e^2-c*d^2)*e)^(1/2)*x*a^3*c^2*d^3*e^7-3795*(
(a*e^2-c*d^2)*e)^(1/2)*x*a^2*c^3*d^5*e^5-2673*((a*e^2-c*d^2)*e)^(1/2)*x^2*a^2*c^3*d^4*e^6-693*((a*e^2-c*d^2)*e
)^(1/2)*x^3*a^2*c^3*d^3*e^7+198*((a*e^2-c*d^2)*e)^(1/2)*x^2*a^3*c^2*d^2*e^8-4620*((a*e^2-c*d^2)*e)^(1/2)*x^4*a
*c^4*d^4*e^6-17094*((a*e^2-c*d^2)*e)^(1/2)*x^3*a*c^4*d^5*e^5-22968*((a*e^2-c*d^2)*e)^(1/2)*x^2*a*c^4*d^6*e^4-1
2782*((a*e^2-c*d^2)*e)^(1/2)*x*a*c^4*d^7*e^3+3465*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^5*c^5
*d^5*e^6*(c*d*x+a*e)^(1/2)+13860*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^4*c^5*d^6*e^5*(c*d*x+a
*e)^(1/2)+20790*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^3*c^5*d^7*e^4*(c*d*x+a*e)^(1/2)+13860*a
rctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x^2*c^5*d^8*e^3*(c*d*x+a*e)^(1/2)+3465*arctanh((c*d*x+a*e)
^(1/2)/((a*e^2-c*d^2)*e)^(1/2)*e)*x*c^5*d^9*e^2*(c*d*x+a*e)^(1/2)+3465*arctanh((c*d*x+a*e)^(1/2)/((a*e^2-c*d^2
)*e)^(1/2)*e)*a*c^4*d^8*e^3*(c*d*x+a*e)^(1/2))/(e*x+d)^(9/2)/(c*d*x+a*e)^2/(a*e^2-c*d^2)^6/((a*e^2-c*d^2)*e)^(
1/2)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (c d e x^{2} + a d e + {\left (c d^{2} + a e^{2}\right )} x\right )}^{\frac {5}{2}} {\left (e x + d\right )}^{\frac {5}{2}}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)^(5/2)/(a*d*e+(a*e^2+c*d^2)*x+c*d*e*x^2)^(5/2),x, algorithm="maxima")

[Out]

integrate(1/((c*d*e*x^2 + a*d*e + (c*d^2 + a*e^2)*x)^(5/2)*(e*x + d)^(5/2)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {1}{{\left (d+e\,x\right )}^{5/2}\,{\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^{5/2}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((d + e*x)^(5/2)*(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(5/2)),x)

[Out]

int(1/((d + e*x)^(5/2)*(x*(a*e^2 + c*d^2) + a*d*e + c*d*e*x^2)^(5/2)), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(e*x+d)**(5/2)/(a*d*e+(a*e**2+c*d**2)*x+c*d*e*x**2)**(5/2),x)

[Out]

Timed out

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